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Mathematics

The ratio in which the line segment joining A(2, -3) and B(5, 6) is divided by x-axis is :

  1. 1 : 2

  2. 2 : 1

  3. 3 : 5

  4. 2 : 3

Section Formula

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Answer

Let the point where x-axis intersects the line segment be P(x, 0).

Let the ratio in which P divides AB be m1 : m2.

The ratio in which the line segment joining A(2, -3) and B(6, 5) is divided by x-axis is : Reflection, RSA Mathematics Solutions ICSE Class 10.

By section-formula (using y–coordinate),

y=(m1y2+m2y1m1+m2)0=m1×5+m2×(3)m1+m20=5m13m25m1=3m2m1m2=35.\Rightarrow y = \Big(\dfrac{m1y2 + m2y1}{m1 + m2}\Big) \\[1em] \Rightarrow 0 = \dfrac{m1 \times 5 + m2 \times (-3)}{m1 + m2} \\[1em] \Rightarrow 0 = 5m1 - 3m2 \\[1em] \Rightarrow 5m1 = 3m2 \\[1em] \Rightarrow \dfrac{m1}{m2} = \dfrac{3}{5}.

Thus, the required ratio is 3 : 5.

Hence, Option 3 is the correct option.

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