$\dfrac{4}{9} \div\ ? = \dfrac{-8}{15}$

1. $\dfrac{-32}{45}$

2. $\dfrac{-8}{5}$

3. $\dfrac{-9}{10}$

4. $\dfrac{-5}{6}$

Between any two given rational numbers we can find

1. one and only one rational number

2. only two rational numbers

3. only ten rational numbers

4. infinitely many rational numbers

Identify a rational number between $\dfrac{1}{3} \text{ and } \dfrac{4}{5}$.

1. $\dfrac{1}{4}$

2. $\dfrac{9}{10}$

3. $\dfrac{17}{30}$

4. $1\dfrac{7}{10}$

The arrangement of rational numbers $\dfrac{-7}{10}, \dfrac{5}{-8}, \dfrac{2}{-3}$, in ascending order is

1. $\dfrac{2}{-3}, \dfrac{5}{-8}, \dfrac{-7}{10}$

2. $\dfrac{-7}{10}, \dfrac{2}{-3}, \dfrac{5}{-8}$

3. $\dfrac{5}{-8}, \dfrac{-7}{10}, \dfrac{2}{-3}$

4. $\dfrac{-7}{10}, \dfrac{5}{-8}, \dfrac{2}{-3}$