By what rational number should 258\dfrac{25}{8}825 be multiplied to get −207\dfrac{-20}{7}7−20 ?
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Let the required number be x. Then,
258×x=−207⇒x=−207÷258=−207×825[Reciprocal of 258 is 825]=−47×85[Dividing 20 and 25 by 5]=−4×87×5=−3235\dfrac{25}{8} \times x = \dfrac{-20}{7} \\[1em] \Rightarrow x = \dfrac{-20}{7} \div \dfrac{25}{8} \\[1em] = \dfrac{-20}{7} \times \dfrac{8}{25} \quad \left[\text{Reciprocal of } \dfrac{25}{8} \text{ is } \dfrac{8}{25}\right] \\[1em] = \dfrac{-4}{7} \times \dfrac{8}{5} \quad \text{[Dividing 20 and 25 by 5]} \\[1em] = \dfrac{-4 \times 8}{7 \times 5} \\[1em] = \dfrac{-32}{35}825×x=7−20⇒x=7−20÷825=7−20×258[Reciprocal of 825 is 258]=7−4×58[Dividing 20 and 25 by 5]=7×5−4×8=35−32
The required number is −3235\dfrac{-32}{35}35−32.
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