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Mathematics

Rationalize the denominator:

1(253)\dfrac{1}{(2\sqrt{5} - \sqrt{3})}.

Rational Irrational Nos

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Answer

Rationalizing the denominator,

1(253)×(25+3)(25+3)(25+3)(25)2(3)2(25+3)203(25+3)17\Rightarrow \dfrac{1}{(2\sqrt{5} - \sqrt{3})} \times \dfrac{(2\sqrt{5} + \sqrt{3})} {(2\sqrt{5} + \sqrt{3})} \\[1em] \Rightarrow \dfrac{(2\sqrt{5} + \sqrt{3})} {(2\sqrt{5})^2 - (\sqrt{3})^2} \\[1em] \Rightarrow \dfrac{(2\sqrt{5} + \sqrt{3})} {20 - 3} \\[1em] \Rightarrow \dfrac{(2\sqrt{5} + \sqrt{3})} {17} \\[1em]

Hence, on rationalizing 1(253)=(25+3)17\dfrac{1}{(2\sqrt{5} - \sqrt{3})} = \dfrac{(2\sqrt{5} + \sqrt{3})}{17}.

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