Rationalize the denominator:

$\dfrac{1}{(3 + \sqrt{5})}$.

Rationalizing the denominator,

$\Rightarrow \dfrac{1}{(3 + \sqrt{5})} \times \dfrac{(3 - \sqrt{5})} {(3 - \sqrt{5})} \\[1em] \Rightarrow \dfrac{(3 - \sqrt{5})} {(3)^2 - (\sqrt{5})^2} \\[1em] \Rightarrow \dfrac{(3 - \sqrt{5})} {9 - 5} \\[1em] \Rightarrow \dfrac{(3 - \sqrt{5})} {4} \\[1em]$

Hence, on rationalizing $\dfrac{1}{(3 + \sqrt{5})} = \dfrac{(3 - \sqrt{5})} {4}$.