Replace '$\boxed{\phantom{653}}$' by an appropriate symbol '< or >' between the given fractions:

(i) $\dfrac{5}{6} \boxed{\phantom{653}} \dfrac{13}{15}$

(ii) $\dfrac{4}{5}$ $\boxed{\phantom{653}}$ $\dfrac{7}{9}$

(iii) $\dfrac{11}{12}$ $\boxed{\phantom{653}}$ $\dfrac{13}{14}$

(i) $\dfrac{5}{6}$ and $\dfrac{13}{15}$

By cross multiplication,

5 × 15 = 75 and 6 × 13 = 78.

Since 75 < 78, therefore, $\dfrac{5}{6} \lt \dfrac{13}{15}$.

Hence, $\dfrac{5}{6} \lt \dfrac{13}{15}$.

(ii) $\dfrac{4}{5}$ and $\dfrac{7}{9}$

By cross multiplication,

4 × 9 = 36 and 5 × 7 = 35.

Since 36 > 35, therefore, $\dfrac{4}{5} \gt \dfrac{7}{9}$.

Hence, $\dfrac{4}{5} \gt \dfrac{7}{9}$.

(iii) $\dfrac{11}{12}$ and $\dfrac{13}{14}$

By cross multiplication,

11 × 14 = 154 and 12 × 13 = 156.

Since 154 < 156, therefore, $\dfrac{11}{12} \lt \dfrac{13}{14}$.

Hence, $\dfrac{11}{12} \lt \dfrac{13}{14}$.