Rohit borrowed ₹ 24,000 at 7.5 percent per year. How much money will he pay at the end of 4 years to clear his debt?

Given:

P = ₹ 24,000

R = 7.5%

T = 4 years

$\because \text{S.I.} = ₹ \Big(\dfrac{P \times R \times T}{100}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ \Big(\dfrac{24,000 \times 7.5 \times 4}{100}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ \dfrac{7,20,000}{100}\\[1em] \Rightarrow \text{S.I.} = ₹ 7,200$ And $\because \text{A = P + S.I.}\\[1em] \Rightarrow \text{A = ₹ 24,000 + ₹ 7,200}\\[1em] \Rightarrow \text{A = ₹ 31,200}\\[1em]$

Hence, Rohit will pay ₹ 31,200 at the end of 4 years.