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Mathematics

Rohit borrows ₹ 86000 from Arun for two years at 5% per annum simple interest. He immediately lends out this money to Akshay at 5% compound interest compounded annually for the same period. Calculate Rohit's profit in transaction at the end of two years.

Compound Interest

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Answer

Given,

P = ₹ 86000

Rate of interest = 5%

Time = 2 years

Calculating S.I. :

S.I. = P×R×T100=86000×5×2100\dfrac{P \times R \times T}{100} = \dfrac{86000 \times 5 \times 2}{100} = ₹ 8600.

Calculating C.I. :

C.I. = A - P

C.I.=P(1+r100)nP=86000×(1+5100)286000=86000×(105100)286000=86000×(2120)286000=86000×44140086000=9481586000=8815.C.I. = P\Big(1 + \dfrac{r}{100}\Big)^n - P \\[1em] = 86000 \times \Big(1 + \dfrac{5}{100}\Big)^2 - 86000 \\[1em] = 86000 \times \Big(\dfrac{105}{100}\Big)^2 - 86000 \\[1em] = 86000 \times \Big(\dfrac{21}{20}\Big)^2 - 86000 \\[1em] = 86000 \times \dfrac{441}{400} - 86000 \\[1em] = 94815 - 86000 \\[1em] = ₹ 8815.

Rohit's profit = Interest received by him - Interest paid by him

= ₹ 8815 - ₹ 8600 = ₹ 215.

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