Mathematics
The roots of the equation px2 + qx + r = 0, where p 0, are given by: 1. x = (-p± √(q^2 - pr)) / 2p 2. x = (-q± √(q^2 - 2pr)) / 4p 3. x = (-q± √(q^2 - 4pr)) / 2p 4. x = (-q± √(q^2 - 4pr)) / 2q
Related Questions
If a, b, c are rational, prove that the roots of the equation (b - c)x2 + (c - a)x + (a - b) = 0 are also rational.
The degree of a quadratic equation is :
1
2
3
none of these
The discriminant of the quadratic equation ax2 + bx + c = 0, a ≠ 0 is given by:
b2 - 2ac
b2 - ac
b2 - 4ac
none of these
For real roots of a quadratic equation, the discriminant must be:
greater than or equal to zero
greater than zero
less than or equal to zero
less than zero