If the roots of equation x^2 - 6x + k = 0 are real and distinct, then value of k is : 1. -9 2. -6 3. 6 4. 9

Given, Roots of equation x2 - 6x + k = 0 are real and distinct. ∴ D 0 ⇒ b2 - 4ac 0 ⇒ (-6)2 - 4 × 1 × k 0 ⇒ 36 - 4k 0 ⇒ 4k 36 ⇒ k ⇒ k 9. Hence, Option 4 is the correct option.

Mathematics

If the roots of equation x² - 6x + k = 0 are real and distinct, then value of k is :
> -9
> -6
< 6
< 9

Quadratic Equations

ICSE Sp 2024

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Answer

Given,

Roots of equation x² - 6x + k = 0 are real and distinct.

∴ D > 0

⇒ b² - 4ac > 0

⇒ (-6)² - 4 × 1 × k > 0

⇒ 36 - 4k > 0

⇒ 4k < 36

⇒ k < $\dfrac{36}{4}$

⇒ k < 9.

Hence, Option 4 is the correct option.

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Mathematics

If the roots of equation x² - 6x + k = 0 are real and distinct, then value of k is :
> -9
> -6
< 6
< 9

Quadratic Equations

ICSE Sp 2024

Answer

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Mathematics

If the roots of equation x2 - 6x + k = 0 are real and distinct, then value of k is :> -9> -6< 6< 9

Quadratic Equations

ICSE Sp 2024

Answer

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> -9
> -6
< 6
< 9

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A retailer purchased an item for ₹ 1,500 from a wholesaler and sells it to a customer at 10% profit. The sales are intra-state and the rate of GST is 10%. The amount of GST paid by the customer is :
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