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Mathematics

The roots of the quadratic equation px2 - qx + r = 0 are real and equal if :

(a) p2 = 4qr

(b) q2 = 4pr

(c) –q2 = 4pr

(d) p2 > 4qr

Quadratic Equations

ICSE 2024

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Answer

By formula,

D = b2 - 4ac

For equation, px2 - qx + r = 0

D = (-q)2 - 4 × p × r

We know that,

Roots of a quadratic equation are real and equal if discriminant = 0.

⇒ q2 - 4pr = 0

⇒ q2 = 4pr.

Hence, Option 2 is the correct option.

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