Mathematics
The roots of the quadratic equation px2 - qx + r = 0 are real and equal if :
(a) p2 = 4qr
(b) q2 = 4pr
(c) –q2 = 4pr
(d) p2 > 4qr
Quadratic Equations
ICSE 2024
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Answer
By formula,
D = b2 - 4ac
For equation, px2 - qx + r = 0
D = (-q)2 - 4 × p × r
We know that,
Roots of a quadratic equation are real and equal if discriminant = 0.
⇒ q2 - 4pr = 0
⇒ q2 = 4pr.
Hence, Option 2 is the correct option.
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