Chemistry
Sample of impure magnesium is reacted with dilute sulphuric acid to give the respective salt and hydrogen. If 1 g. of the impure sample gave 298.6 cc. of hydrogen at s.t.p. Calculate the % purity of the sample. [Mg = 24, H = 1].
Stoichiometry
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Answer
22400 cc of H2 is produced from 24 g of pure magnesium
∴ 298.6 cc. of H2 is produced from x 298.6 = 0.3199 g of pure magnesium
∴ Percentage Purity = 0.3199 x 100 = 31.99 %
Hence, the % purity of the sample is 31.99 %
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