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Mathematics

If sec A = cosec A and 0° ≤ A ≤ 90°, state the value of A.

Trigonometric Identities

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Answer

sec A = cosec A

1cos A=1sin A\dfrac{1}{\text{cos A}} = \dfrac{1}{\text{sin A}}

sin A = cos A

As we know that sin2 A + cos2 A = 1

⇒ sin2 A + sin2 A = 1

⇒ 2sin2 A = 1

⇒ sin2 A = 12\dfrac{1}{2}

⇒ sin A = 12\dfrac{1}{\sqrt2}

⇒ sin A = sin 45°

⇒ A = 45°

Hence, the value of A = 45°.

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