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Several electric bulbs designed to be used on a 220 V electric supply line, are rated 10 W. How many lamps can be connected in parallel with each other across the two wires of 220 V line if the maximum allowable current is 5 A?

Current Electricity

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Answer

Given,

V = 220 V

P = 10 W

IMax = 5 A

The resistance of the each bulb:

R = V2P=220210=4840\dfrac{\text{V}^2}{\text{P}} = \dfrac{220^2}{10} = 4840 Ω

Assuming n bulbs are connected in parallel

1Req=1R+1R+....n1Req=14840+14840+....n1Req=n4840ΩReq=4840nΩ\dfrac{1}{\text{R}{eq}} = \dfrac{1}{\text{R}} + \dfrac{1}{\text{R}} + ….n \\[1em] \dfrac{1}{\text{R}{eq}} = \dfrac{1}{4840} + \dfrac{1}{4840} + ….n \\[1em] \dfrac{1}{\text{R}{eq}} = \dfrac{\text{n}}{4840} \Omega \\[1em] \Rightarrow \text{R}{eq} = \dfrac{4840}{\text{n}} \Omega

Applying Ohm's Law:

V = IR

220 = 5 x 4840n\dfrac{4840}{\text{n}}

n = 4840×5220\dfrac{4840 \times 5}{220} = 110 lamps

Hence, 110 lamps can be connected in parallel.

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