Show that log (1 + 2 + 3) = log 1 + log 2 + log 3.

Given,

⇒ log (1 + 2 + 3) = log 1 + log 2 + log 3

Solving the R.H.S,

⇒ log 1 + log 2 + log 3

⇒ log (1 × 2 × 3)

⇒ log 6

⇒ log (1 + 2 + 3)

Since,

L.H.S = R.H.S.

Hence, proved that log (1 + 2 + 3) = log 1 + log 2 + log 3.