Show that the point (2, 2) is equidistant from the points (-1, -2) and (-3, 2).

Distance between 2 points (x₁, y₁) and (x₂, y₂) = $\sqrt{(x$2 - x1)^2 + (y2 - y1)^2}

Distance between (2, 2) and (-1, -2) =

$= \sqrt{(-1 - 2)^2 + (-2 - 2)^2}\\[1em] = \sqrt{(-3)^2 + (-4)^2}\\[1em] = \sqrt{9 + 16}\\[1em] = \sqrt{25}\\[1em] = 5$

Distance between (2, 2) and (-3, 2) =

$= \sqrt{(-3 - 2)^2 + (2 - 2)^2}\\[1em] = \sqrt{(-5)^2 + (0)^2}\\[1em] = \sqrt{25}\\[1em] = 5$

Hence, the point (2, 2) is equidistant from the points (-1, -2) and (-3, 2).