Show that the progression 625, 125, 25, 5, 1,1/5 , ..... is a G.P. Write its (i) first term (ii) common ratio (iii) nth term (iv) 10th term

Question

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Given, 625, 125, 25, 5, 1, , ........ Since, ratio between consecutive terms are equal, thus the series is in G.P. a = 625 r = We know that, nth term of a G.P. is given by, Tn = arn - 1 Tn = = = = 55 - n = . 10th term, T10 = 55 - 10 = 5-5 = = . Hence, a = 625, r = , Tn = , T10 = .

Mathematics

Show that the progression 625, 125, 25, 5, 1,1/5 , ..... is a G.P. Write its (i) first term (ii) common ratio (iii) nth term (iv) 10th term

G.P.

Related Questions

Show that the progression 2, 6, 18, 54, 162,….. is a G.P.
Write its:
(i) first term
(ii) common ratio
(iii) nth term
(iv) 8th term.

Mathematics

Show that the progression 625, 125, 25, 5, 1,1/5 , ..... is a G.P. Write its (i) first term (ii) common ratio (iii) nth term (iv) 10th term

G.P.

Related Questions

Show that the progression 2, 6, 18, 54, 162,….. is a G.P.Write its:(i) first term(ii) common ratio(iii) nth term(iv) 8th term.

Show that the progression 2, 6, 18, 54, 162,….. is a G.P.
Write its:
(i) first term
(ii) common ratio
(iii) nth term
(iv) 8th term.