Show that the number 21952 is divisible by 7.

According to the divisibility of 7, take the last digit of the number, double it then subtract the result from the rest of the number, if the resulting number is divisible by 7 then the number is divisible by 7.

The number is 21952.

The last digit is 2 and its double is 4.

Rest of the number = 2195

Subtract 4 from 2195 to get 2195 - 4 = 2191.

Take 2191 as the number.

The last digit is 1 and its double is 2.

Rest of the number = 219

Subtract 2 from 219 to get 219 - 2 = 217

Take 217 as the number.

The last digit is 7 and its double is 14.

Rest of the number = 21

Subtract 14 from 21 to get 21 - 14 = 7 and 7 is divisible by 7.

Hence, 21952 is divisible by 7.