Show that x is irrational, if : (i) x^2 = 6 (ii) x^2 = 0.009 (iii) x^2 = 27

Question

KnowledgeBoat · Accepted Answer

(i) Given, ⇒ x² = 6 ⇒ x = ⇒ x = 2.449..... Since, x is non-terminating as well as non-recurring. Hence, proved that x is irrational. (ii) Given, ⇒ x² = 0.009 ⇒ x = ⇒ x = 0.094..... Since, x is non-terminating as well as non-recurring. Hence, proved that x is irrational. (iii) Given, ⇒ x² = 27 ⇒ x = ⇒ x = 5.196..... Since, x is non-terminating as well as non-recurring. Hence, proved that x is irrational.

Mathematics

Show that x is irrational, if :
(i) x² = 6
(ii) x² = 0.009
(iii) x² = 27

Rational Irrational Nos

Related Questions

Mathematics

Show that x is irrational, if :(i) x2 = 6(ii) x2 = 0.009(iii) x2 = 27

Rational Irrational Nos

Related Questions

Show that x is irrational, if :
(i) x² = 6
(ii) x² = 0.009
(iii) x² = 27