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Mathematics

(a+b)(a2ab+b2)(a2b+ab2)\dfrac{(a + b)(a^2 - ab + b^2)}{(a^2b + ab^2)} in simplest form is equal to:

  1. ab1+ba\dfrac{a}{b} - 1 + \dfrac{b}{a}

  2. a3b3a2b+ab2\dfrac{a^3 - b^3}{a^2b + ab^2}

  3. a2+b2ab\dfrac{a^2 + b^2}{ab}

  4. none of these

Factorisation

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Answer

Given,

(a+b)(a2ab+b2)(a2b+ab2)(a+b)(a2ab+b2)ab(a+b)(a2ab+b2)aba2ababab+b2abab1+ba\Rightarrow \dfrac{(a + b)(a^2 - ab + b^2)}{(a^2b + ab^2)}\\[1em] \Rightarrow \dfrac{(a + b)(a^2 - ab + b^2)}{ab(a + b)}\\[1em] \Rightarrow \dfrac{(a^2 - ab + b^2)}{ab}\\[1em] \Rightarrow \dfrac{a^2}{ab} - \dfrac{ab}{ab} + \dfrac{b^2}{ab} \\[1em] \Rightarrow \dfrac{a}{b} - 1 + \dfrac{b}{a}

Hence, option 1 is the correct option.

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