Simplify :

$1\dfrac{2}{3} + \dfrac{5}{6}$ of $\dfrac{24}{25}$

We have:

$1\dfrac{2}{3} + \dfrac{5}{6}$ of $\dfrac{24}{25}$

= $\dfrac{5}{3}$ + $\dfrac{5}{6}$ of $\dfrac{24}{25}$ [Converting mixed to improper fraction]

According to BODMAS rule, we solve "of" first

$\begin{array}{ll} = \dfrac{5}{3} + \dfrac{5}{6} \times \dfrac{24}{25} \\ = \dfrac{5}{3} + \dfrac{1}{6} \times \dfrac{24}{5} \\ = \dfrac{5}{3} + \dfrac{24}{30} \\ = \dfrac{5}{3} + \dfrac{4}{5} & \text{[Of simplified]} \\ = \dfrac{25 + 12}{15} = \dfrac{37}{15} & \text{[Addition simplified]} \\ = 2\dfrac{7}{15} & \text{[Converting improper to mixed fraction]} \end{array}$

∴ The answer is $2\dfrac{7}{15}$