Simplify :
83a×25×22a4×211a×2−2a\dfrac{8^{3a} \times 2^5 \times 2^{2a}}{4 \times 2^{11a} \times 2^{-2a}}4×211a×2−2a83a×25×22a
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Simplifying the expression :
⇒83a×25×22a4×211a×2−2a=(23)3a×25×22a22×211a×2−2a=29a×25×22a22×211a×2−2a=29a+5+2a22+11a+(−2a)=211a+529a+2=2(11a+5)−(9a+2)=211a−9a+5−2=22a+3.\Rightarrow \dfrac{8^{3a} \times 2^5 \times 2^{2a}}{4 \times 2^{11a} \times 2^{-2a}} = \dfrac{(2^3)^{3a} \times 2^5 \times 2^{2a}}{2^2 \times 2^{11a} \times 2^{-2a}} \\[1em] = \dfrac{2^{9a} \times 2^5 \times 2^{2a}}{2^2 \times 2^{11a} \times 2^{-2a}} \\[1em] = \dfrac{2^{9a + 5 + 2a}}{2^{2 + 11a + (-2a)}} \\[1em] = \dfrac{2^{11a + 5}}{2^{9a + 2}} \\[1em] = 2^{(11a + 5) - (9a + 2)} \\[1em] = 2^{11a - 9a + 5 - 2} \\[1em] = 2^{2a + 3}.⇒4×211a×2−2a83a×25×22a=22×211a×2−2a(23)3a×25×22a=22×211a×2−2a29a×25×22a=22+11a+(−2a)29a+5+2a=29a+2211a+5=2(11a+5)−(9a+2)=211a−9a+5−2=22a+3.
Hence, 83a×25×22a4×211a×2−2a=22a+3\dfrac{8^{3a} \times 2^5 \times 2^{2a}}{4 \times 2^{11a} \times 2^{-2a}} = 2^{2a + 3}4×211a×2−2a83a×25×22a=22a+3.
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If 2160 = 2a.3b.5c, find a, b and c. Hence, calculate the value of 3a × 2-b × 5-c.
If 1960 = 2a.5b.7c, calculate the value of 2-a.7b.5-c.
3×27n+1+9×33n−18×33n−5×27n\dfrac{3 \times 27^{n + 1} + 9 \times 3^{3n - 1}}{8 \times 3^{3n} - 5 \times 27^n}8×33n−5×27n3×27n+1+9×33n−1
Show that :
(ama−n)m−n×(ana−l)n−l×(ala−m)l−m\Big(\dfrac{a^m}{a^{-n}}\Big)^{m - n} \times \Big(\dfrac{a^n}{a^{-l}}\Big)^{n - l} \times (\dfrac{a^l}{a^{-m}}\Big)^{l - m}(a−nam)m−n×(a−lan)n−l×(a−mal)l−m = 1