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Mathematics

Simplify:

(2x2y3)2(2x^2y^{-3})^{-2}

Exponents

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Answer

(2x2y3)2=(2x2y3)2=(y32x2)2=y64x4=14y6x4(2x^2y^{-3})^{-2}\\[1em] = \Big(\dfrac{2x^2}{y^3}\Big)^{-2}\\[1em] = \Big(\dfrac{y^3}{2x^2}\Big)^2\\[1em] = \dfrac{y^6}{4x^4}\\[1em] = \dfrac{1}{4}y^6x^{-4}

(2x2y3)2=14y6x4(2x^2y^{-3})^{-2} = \dfrac{1}{4}y^6x^{-4}

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