3a×[8b÷4−6{a−(5a−3b−2a)}]
= 3a×[8b÷4−6{a−(5a−3b+2a)}]
= 3a×[8b÷4−6{a−(5a+2a−3b)}]
= 3a×[8b÷4−6{a−(7a−3b)}]
= 3a×[8b÷4−6{a−7a+3b}]
= 3a×[8b÷4−6{−6a+3b}]
= 3a×[8b÷4+36a−18b]
= 3a×[2b+36a−18b]
= 3a×[2b−18b+36a]
= 3a×[−16b+36a]
= −48ab+108a2
Hence, 3a×[8b÷4−6{a−(5a−3b−2a)}]=108a2−48ab