Simplify and express with positive exponents:
(3x2)0,(xy)−2,(−27a9)23(3x^2)^0, (xy)^{-2}, (-27a^9)^{\dfrac{2}{3}}(3x2)0,(xy)−2,(−27a9)32
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(3x2)0 = 1,
(xy)−2=(1xy)2=1x2y2(xy)^{-2} = \Big(\dfrac{1}{xy}\Big)^2 = \dfrac{1}{x^2y^2}(xy)−2=(xy1)2=x2y21
(−27a9)23=[(−3a3)3]23=(−3a3)3×23=(−3a3)2=9a6.(-27a^9)^{\dfrac{2}{3}} = [(-3a^3)^3]^{\dfrac{2}{3}} \\[1em] = (-3a^3)^{3 \times \dfrac{2}{3}} \\[1em] = (-3a^3)^2 \\[1em] = 9a^6.(−27a9)32=[(−3a3)3]32=(−3a3)3×32=(−3a3)2=9a6.
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