Simplify the expression: (−14)+(512)\left(-\dfrac{1}{4}\right) + \left(\dfrac{5}{12}\right)(−41)+(125).
2 Likes
Given, (−14)+(512)\left(-\dfrac{1}{4}\right) + \left(\dfrac{5}{12}\right)(−41)+(125)
L.C.M. of 4 and 12 = 12.
⇒−14+512⇒−1×34×3+512⇒−312+512⇒−3+512⇒212⇒16.\Rightarrow -\dfrac{1}{4} + \dfrac{5}{12} \\[1em] \Rightarrow -\dfrac{1 \times 3}{4 \times 3} + \dfrac{5}{12} \\[1em] \Rightarrow -\dfrac{3}{12} + \dfrac{5}{12} \\[1em] \Rightarrow \dfrac{-3 + 5}{12} \\[1em] \Rightarrow \dfrac{2}{12} \\[1em] \Rightarrow \dfrac{1}{6}.⇒−41+125⇒−4×31×3+125⇒−123+125⇒12−3+5⇒122⇒61.
Hence, (−14)+(512)=16\left(-\dfrac{1}{4}\right) + \left(\dfrac{5}{12}\right) = \dfrac{1}{6}(−41)+(125)=61.
Answered By
1 Like
Represent the rational numbers 23\dfrac{2}{3}32, −54-\dfrac{5}{4}−45 and 1121\dfrac{1}{2}121 on a single number line.
Find three distinct rational numbers that lie strictly between −12-\dfrac{1}{2}−21 and 14\dfrac{1}{4}41.
A tailor has 153415\dfrac{3}{4}1543 metres of fine silk. If making one kurta requires 2142\dfrac{1}{4}241 metres of silk, exactly how many kurtas can he make?
Find three rational numbers between 3.1415 and 3.1416.