Simplify the following:
(2x−3x)(2x+3x)\Big(2x - \dfrac{3}{x}\Big)\Big(2x + \dfrac{3}{x}\Big)(2x−x3)(2x+x3)
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(2x−3x)(2x+3x)=(2x)2−(3x)2=4x2−9x2\Big(2x - \dfrac{3}{x}\Big)\Big(2x + \dfrac{3}{x}\Big) = \Big(2x\Big)^2 - \Big(\dfrac{3}{x}\Big)^2 = 4x^2 - \dfrac{9}{x^2}(2x−x3)(2x+x3)=(2x)2−(x3)2=4x2−x29
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