Simplify the following:
(x+2x−3)(x−2x−3)\Big(x + \dfrac{2}{x} - 3\Big)\Big(x - \dfrac{2}{x} - 3\Big)(x+x2−3)(x−x2−3)
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(x+2x−3)(x−2x−3)\Big(x + \dfrac{2}{x} - 3\Big)\Big(x - \dfrac{2}{x} - 3\Big) \\[1em](x+x2−3)(x−x2−3)
Let (x - 3) = a
Then, the given expression = (a+2x)(a−2x)=(a)2−(2x)2=a2−4x2=(x−3)2−4x2=x2−2(x)(3)+32−4x2x2−6x+9−4x2\Big(a+\dfrac{2}{x}\Big)\Big(a-\dfrac{2}{x}\Big) = \Big(a\Big)^2 - \Big(\dfrac{2}{x}\Big)^2 \\[1em] = a^2 - \dfrac{4}{x^2} = (x-3)^2 - \dfrac{4}{x^2} = x^2 -2(x)(3) + 3^2 - \dfrac{4}{x^2} \\[1em] x^2 - 6x + 9 - \dfrac{4}{x^2}(a+x2)(a−x2)=(a)2−(x2)2=a2−x24=(x−3)2−x24=x2−2(x)(3)+32−x24x2−6x+9−x24
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