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Mathematics

Simplify the following:

(x3x)(x2+3+9x2)\Big(x - \dfrac{3}{x}\Big)\Big(x^2 + 3 + \dfrac{9}{x^2}\Big)

Expansions

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Answer

We know that (a - b)(a2 + ab + b2) = a3 - b3

∴ Given Expression = (x3x)(x2+3+9x2)\Big(x - \dfrac{3}{x}\Big)\Big(x^2 + 3 + \dfrac{9}{x^2}\Big)

=x3(3x)3=x327x3= x^3 - \Big(\dfrac{3}{x}\Big)^3 \\[1em] = x^3 - \dfrac{27}{x^3}

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