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Mathematics

Simplify the following:

5.(25)n+125.(5)2n5.(5)2n+3(25)n+1\dfrac{5.(25)^{n + 1} - 25.(5)^{2n}}{5.(5)^{2n + 3} - (25)^{n + 1}}

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Answer

Given,

5.(25)n+125.(5)2n5.(5)2n+3(25)n+1=5.(52)n+1(52)(5)2n5.(5)2n+3(52)n+1=5.52n+252+2n52n+452n+2=52n+352n+252n+452n+2=52n.5352n.5252n.5452n.52=52n(5352)52n(5452)=1252562525=100600=16.\Rightarrow \dfrac{5.(25)^{n + 1} - 25.(5)^{2n}}{5.(5)^{2n + 3} - (25)^{n + 1}} \\[1em] = \dfrac{5.(5^2)^{n + 1} - (5^2)(5)^{2n}}{5.(5)^{2n + 3} - (5^2)^{n + 1}} \\[1em] = \dfrac{5.5^{2n + 2} - 5^{2 + 2n}}{5^{2n + 4} - 5^{2n + 2}} \\[1em] = \dfrac{5^{2n + 3} - 5^{2n + 2}}{5^{2n + 4} - 5^{2n + 2}} \\[1em] = \dfrac{5^{2n}.5^3 - 5^{2n}.5^2}{5^{2n}.5^4 - 5^{2n}.5^2} \\[1em] = \dfrac{5^{2n}(5^3 - 5^2)}{5^{2n}(5^4 - 5^2)} \\[1em] = \dfrac{125 - 25}{625 - 25} \\[1em] = \dfrac{100}{600} = \dfrac{1}{6}.

Hence, 5.(25)n+125.(5)2n5.(5)2n+3(25)n+1=16\dfrac{5.(25)^{n + 1} - 25.(5)^{2n}}{5.(5)^{2n + 3} - (25)^{n + 1}} = \dfrac{1}{6}.

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