Given,
⇒5.(5)2n+3−(25)n+15.(25)n+1−25.(5)2n=5.(5)2n+3−(52)n+15.(52)n+1−(52)(5)2n=52n+4−52n+25.52n+2−52+2n=52n+4−52n+252n+3−52n+2=52n.54−52n.5252n.53−52n.52=52n(54−52)52n(53−52)=625−25125−25=600100=61.
Hence, 5.(5)2n+3−(25)n+15.(25)n+1−25.(5)2n=61.