Simplify the following:
(32)0+3−4×36+(13)−2(3^2)^0 + 3^{-4} \times 3^6 + \Big(\dfrac{1}{3}\Big)^{-2}(32)0+3−4×36+(31)−2
38 Likes
Given,
⇒(32)0+3−4×36+(13)−2=90+134×36+(3)2=1+134×36+32=1+32+32=1+9+9=19.\Rightarrow (3^2)^0 + 3^{-4} \times 3^6 + \Big(\dfrac{1}{3}\Big)^{-2} \\[1em] = 9^0 + \dfrac{1}{3^4} \times 3^6 + (3)^2 \\[1em] = 1 + \dfrac{1}{3^4} \times 3^6 + 3^2 \\[1em] = 1 + 3^2 + 3^2 \\[1em] = 1 + 9 + 9 = 19.⇒(32)0+3−4×36+(31)−2=90+341×36+(3)2=1+341×36+32=1+32+32=1+9+9=19.
Hence, (32)0+3−4×36÷(13)−2(3^2)^0 + 3^{-4} \times 3^6 ÷ \Big(\dfrac{1}{3}\Big)^{-2}(32)0+3−4×36÷(31)−2 = 19.
Answered By
20 Likes
(3x2)−3×(x9)23(3x^2)^{-3} \times (x^9)^{\dfrac{2}{3}}(3x2)−3×(x9)32
(8x4)13÷x13(8x^4)^{\dfrac{1}{3}} ÷ x^{\dfrac{1}{3}}(8x4)31÷x31
(9)52−3.(5)0−(181)−12(9)^{\dfrac{5}{2}} - 3.(5)^0 - \Big(\dfrac{1}{81}\Big)^{-\dfrac{1}{2}}(9)25−3.(5)0−(811)−21
1634+2(12)−1(3)016^{\dfrac{3}{4}} + 2\Big(\dfrac{1}{2}\Big)^{-1}(3)^01643+2(21)−1(3)0
