Simplify the following :
log4log2\dfrac{\text{log} 4}{\text{log} 2}log2log4
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Given,
⇒log 4log 2⇒log 22log 2⇒2 log 2log 2⇒2.\Rightarrow \dfrac{\text{log 4}}{\text{log 2}} \\[1em] \Rightarrow \dfrac{\text{log 2}^2}{\text{log 2}} \\[1em] \Rightarrow \dfrac{\text{2 log 2}}{\text{log 2}} \\[1em] \Rightarrow 2.⇒log 2log 4⇒log 2log 22⇒log 22 log 2⇒2.
Hence, log4log2\dfrac{\text{log} 4}{\text{log} 2}log2log4 = 2.
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log a3 - log a2
log a3 ÷ log a2
log 8 log 9log 27\dfrac{\text{log 8 log 9}}{\text{log 27}}log 27log 8 log 9
log 27log 3\dfrac{\text{log 27}}{\text{log } \sqrt{3}}log 3log 27
