Simplify the following and express with positive index :
(32)−25÷(125)−23(32)^{-\dfrac{2}{5}} ÷ (125)^{-\dfrac{2}{3}}(32)−52÷(125)−32
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Simplifying the expression :
⇒(32)−25÷(125)−23=(25)−25÷(53)−23=(2)5×−25÷(5)3×−23=(2)−2÷5−2=122÷152=122×52=14×25=254=614.\Rightarrow (32)^{-\dfrac{2}{5}} ÷ (125)^{-\dfrac{2}{3}} = (2^5)^{-\dfrac{2}{5}} ÷ (5^3)^{-\dfrac{2}{3}} \\[1em] = (2)^{5 \times -\dfrac{2}{5}} ÷ (5)^{3 \times -\dfrac{2}{3}} \\[1em] = (2)^{-2} ÷ 5^{-2} \\[1em] = \dfrac{1}{2^2} ÷ \dfrac{1}{5^2} \\[1em] = \dfrac{1}{2^2} \times 5^2 \\[1em] = \dfrac{1}{4} \times 25 \\[1em] = \dfrac{25}{4} = 6\dfrac{1}{4}.⇒(32)−52÷(125)−32=(25)−52÷(53)−32=(2)5×−52÷(5)3×−32=(2)−2÷5−2=221÷521=221×52=41×25=425=641.
Hence, (32)−25÷(125)−23=614(32)^{-\dfrac{2}{5}} ÷ (125)^{-\dfrac{2}{3}} = 6\dfrac{1}{4}(32)−52÷(125)−32=641.
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