If sin θ = $\dfrac{3}{5}$ and θ is an acute angle, find the values of cos θ and tan θ.

sin θ = $\dfrac{\text{perpendicular}}{\text{hypotenuse}} = \dfrac{3}{5}$

Let perpendicular = 3x and hypotenuse = 5x

By using Pythagoras theorem, we get :

Hypotenuse² = Base² + Perpendicular²

Base² = Hypotenuse² - Perpendicular²

Base² = (5x)² - (3x)²

Base² = 25x² - 9x²

Base² = 16x²

Base = 4x

cos θ = $\dfrac{\text{base}}{\text{hypotenuse}} = \dfrac{4x}{5x} = \dfrac{4}{5}$

tan θ = $\dfrac{\text{perpendicular}}{\text{base}} = \dfrac{3x}{4x} = \dfrac{3}{4}$