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Mathematics

If sin θ + cosec θ = 2, then sin3 θ + cosec3 θ is equal to :

  1. 2

  2. 2 sin θ

  3. −2 sin θ

  4. 2 cos θ

Trigonometric Identities

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Answer

sin θ + cosec θ = 2

Let,

⇒ sin θ = x

⇒ cosec θ = 1x\dfrac{1}{x}

x+1x=2x2+1x=2x2+1=2xx2+12x=0(x1)2=0x=1\Rightarrow x + \dfrac{1}{x} = 2 \\[1em] \Rightarrow \dfrac{x^2 + 1}{x} = 2 \\[1em] \Rightarrow x^2 + 1 = 2x \\[1em] \Rightarrow x^2 + 1 - 2x = 0 \\[1em] \Rightarrow (x - 1)^2 = 0 \\[1em] \Rightarrow x = 1

Hence,

sin θ = 1 and cosec θ = 1

⇒ sin3 θ + cosec3 θ

⇒ 13 + 13

⇒ 2

Hence, option 1 is the correct option.

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