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Mathematics

The slope of a line perpendicular to the line, 3x = 4y – 10, is :

  1. 43\dfrac{4}{3}

  2. –43–\dfrac{4}{3}

  3. 34\dfrac{3}{4}

  4. −34\dfrac{-3}{4}

Straight Line Eq

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Answer

Solving,

⇒ 3x = 4y - 10

⇒ 4y = 3x + 10

⇒y=34x+104\Rightarrow y = \dfrac{3}{4}x + \dfrac{10}{4}.

The slope of the given line is m=34m = \dfrac{3}{4}.

Since the required line is perpendicular, the product of the slopes must be -1.

Let slope of required line be a, then :

⇒ m × a = -1

⇒ 34\dfrac{3}{4} × a = -1

⇒ a = −43\dfrac{-4}{3}.

Hence, option 2 is the correct option.

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