Solution of equations x + y = 2.1 and x - y = 0.3 is : 1. x = 1.2, y = 0.9 2. x = 1.2, y = -0.9 3. x = -1.2, y = 0.9 4. x = -1.2, y = -0.9

Given, Equations : ⇒ x + y = 2.1 ..........(1) ⇒ x - y = 0.3 ............(2) Subtracting equation (2) from (1), we get : ⇒ x + y - (x - y) = 2.1 - 0.3 ⇒ x - x + y - (-y) = 1.8 ⇒ 2y = 1.8 ⇒ y = = 0.9 Substituting value of y in equation (1), we get : ⇒ x + 0.9 = 2.1 ⇒ x = 2.1 - 0.9 = 1.2 Hence, Option 1 is the correct option.

Mathematics

Solution of equations x + y = 2.1 and x - y = 0.3 is :
x = 1.2, y = 0.9
x = 1.2, y = -0.9
x = -1.2, y = 0.9
x = -1.2, y = -0.9

Linear Equations

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Answer

Given,

Equations :

⇒ x + y = 2.1 ……….(1)

⇒ x - y = 0.3 …………(2)

Subtracting equation (2) from (1), we get :

⇒ x + y - (x - y) = 2.1 - 0.3

⇒ x - x + y - (-y) = 1.8

⇒ 2y = 1.8

⇒ y = $\dfrac{1.8}{2}$ = 0.9

Substituting value of y in equation (1), we get :

⇒ x + 0.9 = 2.1

⇒ x = 2.1 - 0.9 = 1.2

Hence, Option 1 is the correct option.

Answered By

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Mathematics

Solution of equations x + y = 2.1 and x - y = 0.3 is :
x = 1.2, y = 0.9
x = 1.2, y = -0.9
x = -1.2, y = 0.9
x = -1.2, y = -0.9

Linear Equations

Answer

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Solution of equations $\dfrac{x + 8}{5} - \dfrac{2y - 4}{3} = 0$ and y - x = 3 is :
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Mathematics

Solution of equations x + y = 2.1 and x - y = 0.3 is :x = 1.2, y = 0.9x = 1.2, y = -0.9x = -1.2, y = 0.9x = -1.2, y = -0.9

Linear Equations

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Solution of equations x - 2y = 7 and 2x - y = 8 is :x = 3, y = 2x = -3, y = 2x = 3, y = -2x = -3, y = -2

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Solution of equations x + y = 2.1 and x - y = 0.3 is :
x = 1.2, y = 0.9
x = 1.2, y = -0.9
x = -1.2, y = 0.9
x = -1.2, y = -0.9

Solution of equations x - 2y = 7 and 2x - y = 8 is :
x = 3, y = 2
x = -3, y = 2
x = 3, y = -2
x = -3, y = -2

Solution of equations $\dfrac{x}{2} - \dfrac{y}{3} = 0 \text{ and } \dfrac{x}{2} + \dfrac{y}{3} = 6$ is :
x = 6, y = -9
x = 6, y = 9
x = -6, y = -9
x = -6, y = 9

Solution of equations $\dfrac{x + 8}{5} - \dfrac{2y - 4}{3} = 0$ and y - x = 3 is :
x = 2, y = 5
x = -2, y = 5
x = 2, y = -5
x = -2, y = -5