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Mathematics

Solve the following equation and check your answer:

83x5x+31=23\dfrac{8 - 3x}{5x + 31} = \dfrac{2}{3}

Linear Eqns One Variable

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Answer

We have:

=83x5x+31=233(83x)=2(5x+31)[By cross multiplication]249x=10x+622462=10x+9x[Transposing -9x to RHS and +62 to LHS]38=19xx=3819\phantom{=} \dfrac{8 - 3x}{5x + 31} = \dfrac{2}{3} \\[1em] \Rightarrow 3(8 - 3x) = 2(5x + 31) \quad \text{[By cross multiplication]} \\[1em] \Rightarrow 24 - 9x = 10x + 62 \\[1em] \Rightarrow 24 - 62 = 10x + 9x \quad \text{[Transposing -9x to RHS and +62 to LHS]} \\[1em] \Rightarrow -38 = 19x \\[1em] \Rightarrow x = \dfrac{-38}{19} \\[1em]

∴ x = -2

Check:

LHS = 83x5x+31\dfrac{8 - 3x}{5x + 31}

= 83(2)5(2)+31\dfrac{8 - 3(-2)}{5(-2) + 31}

= 1421\dfrac{14}{21}

= 23\dfrac{2}{3}

RHS = 23\dfrac{2}{3}

Hence, LHS = RHS.

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