Solve the following equation and check your answer:
8−3x5x+31=23\dfrac{8 - 3x}{5x + 31} = \dfrac{2}{3}5x+318−3x=32
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We have:
=8−3x5x+31=23⇒3(8−3x)=2(5x+31)[By cross multiplication]⇒24−9x=10x+62⇒24−62=10x+9x[Transposing -9x to RHS and +62 to LHS]⇒−38=19x⇒x=−3819\phantom{=} \dfrac{8 - 3x}{5x + 31} = \dfrac{2}{3} \\[1em] \Rightarrow 3(8 - 3x) = 2(5x + 31) \quad \text{[By cross multiplication]} \\[1em] \Rightarrow 24 - 9x = 10x + 62 \\[1em] \Rightarrow 24 - 62 = 10x + 9x \quad \text{[Transposing -9x to RHS and +62 to LHS]} \\[1em] \Rightarrow -38 = 19x \\[1em] \Rightarrow x = \dfrac{-38}{19} \\[1em]=5x+318−3x=32⇒3(8−3x)=2(5x+31)[By cross multiplication]⇒24−9x=10x+62⇒24−62=10x+9x[Transposing -9x to RHS and +62 to LHS]⇒−38=19x⇒x=19−38
∴ x = -2
Check:
LHS = 8−3x5x+31\dfrac{8 - 3x}{5x + 31}5x+318−3x
= 8−3(−2)5(−2)+31\dfrac{8 - 3(-2)}{5(-2) + 31}5(−2)+318−3(−2)
= 1421\dfrac{14}{21}2114
= 23\dfrac{2}{3}32
RHS = 23\dfrac{2}{3}32
Hence, LHS = RHS.
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p - (2p + 5) - 5(1 - 2p) = 2(3 + 4p) - 3(p - 4)
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x3+x4=14\dfrac{x}{3}+\dfrac{x}{4} = 143x+4x=14
2x3+4x=42\dfrac{2x}{3} + 4x = 4232x+4x=42