Solve the following equation and check your answer:

$2\Big(y -\dfrac{5}{2}\Big) = 0.3$

We have:

$\phantom{=} 2\Big(y -\dfrac{5}{2}\Big) = 0.3 \\[1em] \Rightarrow 2y - 2 \times \dfrac{5}{2} = 0.3 \quad \text{[Removing brackets]} \\[1em] \Rightarrow 2y - 5 = 0.3 \\[1em] \Rightarrow 2y = 0.3 + 5 \quad\text{[Transposing -5 to RHS]} \\[1em] \Rightarrow 2y = 5.3 \\[1em] \Rightarrow y = \dfrac{5.3}{2}$

∴ y = 2.65

Check:

LHS = $2\left(y - \dfrac{5}{2}\right)$

= 2(2.65 - 2.5)

= 2(0.15) = 0.3

RHS = 0.3

Hence, LHS = RHS.