Solve the following equation by factorization: 3x + 1/7x + 1 = 5x + 1/7x + 5

Question

KnowledgeBoat · Accepted Answer

Given, ⇒ (3x + 1)(7x + 5) = (5x + 1)(7x + 1) ⇒ (21x2 + 15x + 7x + 5) = (35x2 + 5x + 7x + 1) ⇒ (21x2 + 22x + 5) = (35x2 + 12x + 1) ⇒ (35x2 + 12x + 1) - (21x2 + 22x + 5) = 0 ⇒ 35x2 + 12x + 1 - 21x2 - 22x - 5 = 0 ⇒ 14x2 - 10x - 4 = 0 ⇒ 2(7x2 - 5x - 2) = 0 ⇒ 7x2 - 5x - 2 = 0 ⇒ 7x2 - 7x + 2x - 2 = 0 ⇒ 7x(x - 1) + 2(x - 1) = 0 ⇒ (7x + 2)(x - 1) = 0 ⇒ (7x + 2) = 0 or (x - 1) = 0 [Using Zero-product rule] ⇒ 7x = -2 or x = 1 ⇒ x = or x = 1. Hence, .

Mathematics

Solve the following equation by factorization: 3x + 1/7x + 1 = 5x + 1/7x + 5

Quadratic Equations

Related Questions