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Mathematics

Solve the following linear equations:

(i) 5(x + 1) = 25

(ii) 2(3x − 1) = 10

(iii) 3x14=11\dfrac{3x - 1}{4} = 11

Simple Equations

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Answer

(i) We have:

5(x + 1) = 25

⇒ x + 1 = 5     [Dividing both sides by 5]

⇒ x = 5 − 1     [Transposing +1 to RHS]

∴ x = 4.

(ii) We have:

2(3x − 1) = 10

⇒ 3x − 1 = 5     [Dividing both sides by 2]

⇒ 3x = 5 + 1     [Transposing −1 to RHS]

⇒ 3x = 6

x=63x = \dfrac{6}{3}

∴ x = 2.

(iii) We have:

3x14=11\dfrac{3x - 1}{4} = 11

⇒ 3x − 1 = 11 × 4     [Multiplying both sides by 4]

⇒ 3x − 1 = 44

⇒ 3x = 44 + 1 = 45

⇒ x = 453\dfrac{45}{3}

⇒ x = 15

∴ x = 15.

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