Solve for x : 2^5x - 1 = 4 × 2^3x + 1

Question

KnowledgeBoat · Accepted Answer

Given, ⇒ 2^{5x - 1} = 4 × 2^{3x + 1} ⇒ 2^{5x - 1} = 2² × 2^{3x + 1} ⇒ 2^{5x - 1} = 2^{2 + 3x + 1} ⇒ 2^{5x - 1} = 2^{3x + 3} ⇒ 5x - 1 = 3x + 3 ⇒ 5x - 3x = 3 + 1 ⇒ 2x = 4 ⇒ x = = 2. Hence, x = 2.

Mathematics

Solve for x :
2^{5x - 1} = 4 × 2^{3x + 1}

Indices

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