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Mathematics

Solve for x:
log x + log 5 = 2log 3

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Given,

⇒ log x + log 5 = 2log 3

⇒ log x = log 3² - log 5

⇒ log x = log 9 - log 5

⇒ log x = log $\dfrac{9}{5}$

⇒ x = $\dfrac{9}{5}$ .

Hence, $x = \dfrac{9}{5}$ .

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