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Mathematics

Solve for x, logx 155=2logx 3515\sqrt{5} = 2 - \text{log}_x \space 3\sqrt{5}

Logarithms

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Answer

Given,

logx 155=2logx 35logx 155+logx 35=2logx (155×35)=2logx 225=2x2=225x=225=15.\Rightarrow \text{log}x \space 15\sqrt{5} = 2 - \text{log}x \space 3\sqrt{5} \\[1em] \Rightarrow \text{log}x \space 15\sqrt{5} + \text{log}x \space 3\sqrt{5} = 2 \\[1em] \Rightarrow \text{log}x \space (15\sqrt{5} \times 3\sqrt{5}) = 2 \\[1em] \Rightarrow \text{log}x \space 225 = 2 \\[1em] \Rightarrow x^2 = 225 \\[1em] \Rightarrow x = \sqrt{225} = 15.

Hence, x = 15.

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