Solve the following equation:

(2x + 3)(x - 4) = 6

Given, (2x + 3)(x - 4) = 6.

⇒ 2x² - 8x + 3x - 12 = 6

⇒ 2x² - 5x - 12 - 6 = 0

⇒ 2x² - 5x - 18 = 0

⇒ 2x² - 9x + 4x - 18 = 0

⇒ x(2x - 9) + 2(2x - 9) = 0

⇒ (x + 2)(2x - 9) = 0

⇒ x + 2 = 0 or 2x - 9 = 0

⇒ x = -2 or 2x = 9

⇒ x = -2 or x = $\dfrac{9}{2}$.

Hence, roots of the given equations are -2, $\dfrac{9}{2}$.