Solve the following equation:

3x² - 4x - 4 = 0

Given, 3x² - 4x - 4 = 0.

⇒ 3x² - 6x + 2x - 4 = 0

⇒ 3x(x - 2) + 2(x - 2) = 0

⇒ (3x + 2)(x - 2) = 0

⇒ 3x + 2 = 0 or x - 2 = 0

⇒ 3x = -2 or x = 2

⇒ x = $-\dfrac{2}{3}$ or x = 2.

Hence, roots of the given equations are 2, $-\dfrac{2}{3}$