Solve the following equation by factorisation:
(2x - 3)2 = 49
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⇒ (2x - 3)2 = 72
⇒ (2x - 3)2 - 72 = 0
As, (a2 - b2) = (a + b)(a - b)
⇒ (2x - 3 + 7)(2x - 3 - 7) = 0
⇒ (2x + 4)(2x - 10) = 0
⇒ 2x + 4 = 0 or 2x - 10 = 0 [Using Zero-product rule]
⇒ 2x = -4 or 2x = 10
⇒ x = -2 or x = 5.
Hence, x = -2 or x = 5.
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(x + 1)(2x + 8) = (x + 7)(x + 3)
4(2x - 3)2 - (2x - 3) - 14 = 0