Solve 4(2x - 3)^2 - (2x - 3) - 14 = 0 by factorisation

Question

KnowledgeBoat · Accepted Answer

4(2x - 3)² - (2x - 3) - 14 = 0 ⇒ 4(4x² + 9 - 12x) - 2x + 3 - 14 = 0 ⇒ 16x² + 36 - 48x - 2x - 11 = 0 ⇒ 16x² - 50x + 25 = 0 ⇒ 16x² - 40x - 10x + 25 = 0 ⇒ 8x(2x - 5) - 5(2x - 5) = 0 ⇒ (8x - 5)(2x - 5) = 0 ⇒ 8x - 5 = 0 or 2x - 5 = 0 [Using Zero-product rule] ⇒ 8x = 5 or 2x = 5 ⇒ x = or x = . Hence, x = .

Mathematics

Solve the following equation by factorisation:
4(2x - 3)² - (2x - 3) - 14 = 0

Quadratic Equations

Related Questions

Solve the following equation by factorisation:
(2x - 3)² = 49

Solve the following equation by factorisation:
(x + 1)(2x + 8) = (x + 7)(x + 3)

Solve the following equation by factorisation:
2x² - 9x + 10 = 0, when :
(i) x ∈ N
(ii) x ∈ Q.

Mathematics

Solve the following equation by factorisation:4(2x - 3)2 - (2x - 3) - 14 = 0

Quadratic Equations

Related Questions

Solve the following equation by factorisation:(2x - 3)2 = 49

Solve the following equation by factorisation:(x + 1)(2x + 8) = (x + 7)(x + 3)

Solve the following equation by factorisation:2x2 - 9x + 10 = 0, when :(i) x ∈ N(ii) x ∈ Q.

Solve the following equation by factorisation:
4(2x - 3)² - (2x - 3) - 14 = 0

Solve the following equation by factorisation:
(2x - 3)² = 49

Solve the following equation by factorisation:
(x + 1)(2x + 8) = (x + 7)(x + 3)

Solve the following equation by factorisation:
2x² - 9x + 10 = 0, when :
(i) x ∈ N
(ii) x ∈ Q.