Solve the following equation for x and give your answer correct to one decimal place :

5x² + 10x - 3 = 0

Comparing 5x² + 10x - 3 = 0 with ax² + bx + c = 0 we get,

a = 5, b = 10 and c = -3.

We know that,

x = $\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Substituting values of a, b and c in above equation we get,

$\Rightarrow x = \dfrac{-(10) \pm \sqrt{(10)^2 - 4.(5).(-3)}}{2(5)} \\[1em] = \dfrac{-10 \pm \sqrt{100 + 60}}{10} \\[1em] = \dfrac{-10 \pm \sqrt{160}}{10} \\[1em] = \dfrac{-10 \pm 4\sqrt{10}}{10} \\[1em] = \dfrac{-10 \pm 12.8}{10} \\[1em] = \dfrac{-10 + 12.8}{10} \text{ and } \dfrac{-10 - 12.8}{10} \\[1em] = \dfrac{2.8}{10} \text{ and } \dfrac{-22.8}{10} \\[1em] = 0.28 \text{ and } -2.28 \\[1em] \approx 0.3 \text{ and } -2.3$

Hence, x = 0.3 and -2.3