Solve the following equation for x:
logx14\dfrac{1}{4}41 = -1
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Given,
⇒ logx14\dfrac{1}{4}41 = -1
⇒x−1=14⇒1x=14⇒x=4.\Rightarrow x^{-1} = \dfrac{1}{4} \\[1em] \Rightarrow \dfrac{1}{x} = \dfrac{1}{4} \\[1em] \Rightarrow x = 4.⇒x−1=41⇒x1=41⇒x=4.
Hence, x = 4.
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log4x = 12\dfrac{1}{2}21
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log81x = 32\dfrac{3}{2}23
log9x = 2.5